energy of monatomic gas

$E_{total}=\frac{3}{2}nRT$ where $R=8.3145\mathrm{J}\cdot \mathrm{mo}{\mathrm{l}}^{-1}\cdot {\mathrm{K}}^{-1}$

$E_{avg}=\frac{3}{2}{k}_{B}T$ where $k_B=1.38\cdot 10^{-23}\mathrm{J}/\mathrm{K}$

$E=\frac{3}{2}RT$ (for one mole of monatomic gas)

$E=\frac{3}{2}rT$ (for one gram of monatomic gas)